I take it to mean, there are a lot of $4$-digit numbers you can form from $1,2,3,4,5$; some of them use the same digit more than once (for example, 1231), and some of them don't (for example, 4153); we …

In mathematics, a digit is defined as the mathematical symbol which is used to count any quantity. For example - 1, 2, 3, 4, 5 etc., There are mainly 10 digits in mathematics as mentioned below: 0, 1, 2, 3, …

Dec 8, 2015 · Since there are 9 ways to determine the 1st digit and (10 – 1 = 9) ways to determine the second digit, [9] * [9] = 81 So there are 81 integers from 10-99 with distinct digits. I'm not …

2 I need a formula to find out the total number of positive integers with distinct digits within a given range. Ex: Numbers $231, 123, 259$ have distinct digits while $211, 101, 332$ do not. Example: 1) …

Mar 7, 2020 · Another way: if you consider all four-digit numbers with no repeated digits (including the ones that start with 0), there are $10 \times 9 \times 8 \times 7$ of them. Now count the four-digit …

how many 5 digit numbers are there with distinct digits? Ask Question Asked 12 years, 11 months ago Modified 9 years, 7 months ago

Nov 27, 2015 · Best interpretation of that is "How many numbers with distinct digits are possible, when the product of those digits must be 28?" Well, the prime factorisation of $28$ is $2^2\cdot 7^1$.

Here are two alternate ways to handle the 3-digit case: a) If the last digit is not zero, there are 4 choices for the last digit, 8 choices for the first digit, and 8 choices for the middle digit.

6 How many $4$ digit even numbers have all $4$ digits distinct ? This question has been asked if we replace even with positive. I was solving this Problem like: For first position $1-9$ (No $0$) for next …

For example, the number $11231$ satisfies the condition of being a 5-digit number with exactly $3$ different digits, but doesn't have the first $3$ digits distinct.